4x^2+12x+9=625

Solution for 4x^2+12x+9=625 equation:

4x^2+12x+9=625

We move all terms to the left:

4x^2+12x+9-(625)=0

We add all the numbers together, and all the variables

4x^2+12x-616=0

a = 4; b = 12; c = -616;
Δ = b2-4ac
Δ = 122-4·4·(-616)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-100}{2*4}=\frac{-112}{8}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+100}{2*4}=\frac{88}{8}
=11
$